5n^2+35-2250=0

Solution for 5n^2+35-2250=0 equation:

5n^2+35-2250=0

We add all the numbers together, and all the variables

5n^2-2215=0

a = 5; b = 0; c = -2215;
Δ = b2-4ac
Δ = 02-4·5·(-2215)
Δ = 44300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{44300}=\sqrt{100*443}=\sqrt{100}*\sqrt{443}=10\sqrt{443}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{443}}{2*5}=\frac{0-10\sqrt{443}}{10}
=-\frac{10\sqrt{443}}{10}
=-\sqrt{443}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{443}}{2*5}=\frac{0+10\sqrt{443}}{10}
=\frac{10\sqrt{443}}{10}
=\sqrt{443}
$